Pounds to Kilograms Conversion
Calculator Chatbot

Use this free chatbot calculator to convert pounds (lbs) to kilograms (kg) and vice versa

Frequently Asked Questions (FAQ)

Find answers to common questions about converting from pounds to kilograms

  • What is the definition of "pound"?

    The pound or pound-mass is most commonly known as the international avoirdupois pound, which is legally defined as exactly 0.45359237 kilograms, and which is divided into 16 avoirdupois ounces. The international standard symbol for the avoirdupois pound is lb.

  • What is the definition of "kilogram"?

    The kilogram (also kilogramme) is the base unit of mass in the metric system having the unit symbol kg. It is a widely used measure in science, engineering, and commerce worldwide, and is often called a kilo. The kilogram is about to the mass of one litre of water.

  • What is a pounds (lbs) to kilograms (kg) conversion calculator?

    It is a calculator or tool used to convert lbs (pounds) to kgs (kilograms).

  • What is the formula to convert pounds (lbs) to kilograms (kg)?

    1 pound (lb) is equal to 0.45359237 kilograms (kg).1 lb = 0.45359237 kgThe mass m in kilograms (kg) is equal to the mass m in pounds (lb) times 0.45359237: m(kg) = m(lb) × 0.45359237
    ExampleConvert 10 lb to kilograms: m(kg) = 10 lb × 0.45359237 = 4.536 kg

  • What is the definition of "grams"?

    The gram (alternative spelling: gramme; SI unit symbol: g; Latin: gramma, from Greek γράμμα, grámma) is a metric system unit of mass.
    Originally defined as "the absolute weight of a volume of pure water equal to the cube of the hundredth part of a meter [1 cm^3], and at the temperature of melting ice" (later at 4 °C, the temperature of maximum density of water). However, in a reversal of reference and defined units, a gram is now defined as one-thousandth of the SI base unit, the kilogram, or 1×10−3 kg, which itself is now defined by the International Bureau of Weights and Measures, not in terms of grams, but by "the amount of electricity needed to counteract its force."

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